发信人: SunyZhao (Sams), 信区: Biology
标 题: Re: 哪位大仙知道生化中K cat 的定义是什么
发信站: The unknown SPACE (Tue Nov 7 22:06:44 2000) WWW-POST

V=Kcat*(E)eq

(E).*Km
=Kcat* ------
Km+S K_1 + Kat
In R & H equation (not M & M), Km = --------
K1
When Km >> S, We get:

Vmax = Kcat* (E).

Hehe, just finished the midterm.


【 在 coconut (可可) 的大作中提到: 】
:
: kcat = k2
: k1 k2
: E + S -----> ES -----> E + P
: <-----
: k(-1)
:
: k2 determintes how fast the ES complex is returned to the
: enzyme pool. One can imagine that if an enzyme has a difficulty
: to dissociate from ES, soon [E] would be depleted. k2 is usually
: the slowest step and therefore determines the rate of enzymatic
: reactions. Also, when talking about initial rate, assuming
: that there are large amount of [S], then all enzymes are able to
: bind to substrate, k2[ES] = Vmax = k2[E]initial
:
: 【 在 citytiger (小老虎~在等小兔) 的大作中提到: 】
: : RT，还有它和反应速度V max， 和底物，和酶浓度有什么联系？泄了！
: : 明天要交作业，刚刚开始做就打了我一棒。学校的网坏了，联不上edu
: : 和gov以外的地址，还没法查破破的蛋白质基础，竟然有
: : 这么多的反应动力学和热力学，弄得人人怨声载道。
:
:


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