发信人: stlstl (射天狼), 信区: Biology
标 题: Re: 问大家一个数据统计的问题
发信站: Unknown Space - 未名空间 (Thu Nov 11 10:50:33 2004) WWW-POST

I have to respectfully disagree.
Gardenia is comparing 3 treatments, not 4 experiments. Each treatment gets 4
results which are not consistent. However, in each experiment the treatments
are comparable. In another word, A1~B1~C1 is comparable, so is A4~B4~C4. If I
only want to know whether treatment A and B have significant difference, I
would say paired t-test is suitable.


【 在 happyzhb (不再年青) 的大作中提到: 】
: You are right that you cannot compare between 4 different experiment,
because
: in you case, cell counts in each experiment could vary so much that they are
: not come from the same distribution, that is why you cannot use pair-wised
: t-test between column, because 1, 9, 21, 15, are not from within the same
: distribution. For example, you are testing weight loss of animals, weight
from
: mouse and from lion are different, if you test 4 different animals, and they
: cannot be normalized, you cannot use column-wise paired t-test. In you case,
: if you are sure that your cell count from 4 different experiments are
: comparable from each other, then you can use pair-wise t-test. otherwise,
you
: can use anova, but I am not sure what is the model.
:
: 【 在 gardenia (十六字令) 的大作中提到: 】
: :
: : 打个比方我做一个实验，3种treatment A B C
: : 做了4次实验
: :
: : 结果分别是：
: :
: : A B C
: : 1 1 5 9

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